Get Specified Entry From Zip File Example.
This Java example shows how to get specified entry (i.e. file or
directory) using getEntry method of Java ZipFile class.
Output of Above Java Program
css/print.css found in Zip file
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
public class GetSpecifiedEntry {
public static void main(String args[])
{
try
{
/*
* Open zip file using,
*
* ZipFile(String fileName)
* constructor of the ZipFile class.
*
* This constructor throws IOException for any I/O error.
*/
ZipFile zipFile = new ZipFile("c:/FileIO/WebFiles.zip");
/*
* To get specified entry from opened zip file, use
*
* ZipEntry getEntry(String name)
* method of ZipFile class.
*
* This method returns entry specified by name, or null if
* not found.
*/
ZipEntry zipEntry = zipFile.getEntry("css/print.css");
if(zipEntry != null)
System.out.println("css/print.css found in Zip file");
else
System.out.println("css/print.css not found in Zip file");
/*
* PLEASE VISIT ZipEntry Examples for more details on
* how to process entries.
*/
/*
* close the opened zip file using,
* void close()
* method.
*/
zipFile.close();
}
catch(IOException ioe)
{
System.out.println("Error opening zip file" + ioe);
}
}
}
Output of Above Java Program
css/print.css found in Zip file
