Demonstrate File by Getting the Name and other Information of File

Here is a Java Program to Demonstrate File.

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import java.io.File;   class FileDemo {   static void p(String s) {     System.out.println(s);   }     public static void main(String args[]) {     File f1 = new File("/java/COPYRIGHT");     p("File Name: " + f1.getName());     p("Path: " + f1.getPath());     p("Abs Path: " + f1.getAbsolutePath());     p("Parent: " + f1.getParent());     p(f1.exists() ? "exists" : "does not exist");     p(f1.canWrite() ? "is writeable" : "is not writeable");     p(f1.canRead() ? "is readable" : "is not readable");     p("is " + (f1.isDirectory() ? "" : "not" + " a directory"));     p(f1.isFile() ? "is normal file" : "might be a named pipe");     p(f1.isAbsolute() ? "is absolute" : "is not absolute");     p("File last modified: " + f1.lastModified());     p("File size: " + f1.length() + " Bytes");   } }

Output of Above Java Program
File Name: COPYRIGHT
Path: \java\COPYRIGHT
Abs Path: C:\java\COPYRIGHT
Parent: \java
exists
is writeable
is readable
is
might be a named pipe
is not absolute
File last modified: 1329568044285
File size: 0 Bytes