Demonstrate File by Getting the Name and other Information of File

Here is a Java Program to Demonstrate File.

import java.io.File;

class FileDemo {
  static void p(String s) {
    System.out.println(s);
  }

  public static void main(String args[]) {
    File f1 = new File("/java/COPYRIGHT");
    p("File Name: " + f1.getName());
    p("Path: " + f1.getPath());
    p("Abs Path: " + f1.getAbsolutePath());
    p("Parent: " + f1.getParent());
    p(f1.exists() ? "exists" : "does not exist");
    p(f1.canWrite() ? "is writeable" : "is not writeable");
    p(f1.canRead() ? "is readable" : "is not readable");
    p("is " + (f1.isDirectory() ? "" : "not" + " a directory"));
    p(f1.isFile() ? "is normal file" : "might be a named pipe");
    p(f1.isAbsolute() ? "is absolute" : "is not absolute");
    p("File last modified: " + f1.lastModified());
    p("File size: " + f1.length() + " Bytes");
  }
}

Output of Above Java Program
File Name: COPYRIGHT
Path: \java\COPYRIGHT
Abs Path: C:\java\COPYRIGHT
Parent: \java
exists
is writeable
is readable
is
might be a named pipe
is not absolute
File last modified: 1329568044285
File size: 0 Bytes